The sum of two polynomials is 8 d to the 5th power minus 3 c cubed d squared plus 5 c squared d cubed minus 4 c d to the 4th power plus 9 If one addend is 2 d to the 5th power minus c cubed d squared plus 8 c d to the 4th power plus 1 , what is the other addend?

To find the other addend, subtract the known addend from the sum and combine like terms. The coefficients become 8−2=6 for d⁵, −3−(−1)=−2 for c³d², 5−0=5 for c²d³, −4−8=−12 for cd⁴, and 9−1=8 for the constant. This gives 6d⁵−2c³d²+5c²d³−12cd⁴+8, which is choice B.

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