Question 7 • CMS 2026-2027 NC Math 1 CREDIT RECOVERY
Distribute each term in 4y − 3 across the second parentheses: 4y(2y² + 3y − 5) gives 8y³ + 12y² − 20y, and −3(2y² + 3y − 5) gives −6y² − 9y + 15. Combine like terms to get 8y³ + 6y² − 29y + 15, which is choice A.
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