What is the product of A plus 3 and negative 2 A squared plus 15 A plus 6 b squared ?

Distribute each term in A + 3 across −2A² + 15A + 6b². This gives −2A³ + 15A² + 6Ab² − 6A² + 45A + 18b². Combine the A² terms, 15A² − 6A² = 9A², to get −2A³ + 9A² + 45A + 6Ab² + 18b², which is choice C.

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