Question 2 • Algebra 1
Divide the leading terms: 2y² ÷ 2y = y. Subtract y(2y + 4) = 2y² + 4y from 2y² + 8 to get −4y + 8. Then divide −4y by 2y to get −2; subtract −2(2y + 4) = −4y − 8, leaving a remainder of 16. The result is y − 2 + 16/(2y + 4), which is choice B.
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