What is the solution to log sub 2 of 9 x minus the log base 2 of 3 is equal to 3 ?

Use the quotient rule for logarithms: log₂(9x) − log₂(3) = log₂(9x ÷ 3) = log₂(3x). Since log₂(3x) = 3, convert to exponential form to get 3x = 2³ = 8. Dividing by 3 gives x = 8/3, so the correct choice is “x is equal to 8 thirds.”

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