Question 10 • Mathematics III
Joe earns 12 × 6 = 72 points for the answers he knows. On each of the 4 questions where he eliminates 2 choices, his chance of being correct is 1/3, so those questions contribute 4 × (1/3 × 6) = 8 expected points. On each of the other 9 questions, his chance is 1/5, contributing 9 × (1/5 × 6) = 10.8 expected points. His expected total is 72 + 8 + 10.8 = 90.8 points, choice D.
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