5
lesson pretestMultiple Choice

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Question 5 • Mathematics III

A charity is holding a raffle to raise money. There is one car worth 30 dollars comma 000 and five 100 dollars gift cards being raffled off. Each ticket costs 20 dollars , and there are a total of 5 comma 000 tickets being sold. Which equation correctly depicts the calculation of the expected value for a ticket?

Answer
A
30 comma 000 times open paren 1 over 5000 close paren plus 100 times open paren 1 over 1000 close paren plus negative 20 times open paren 2497 over 2500 close paren is equal to cap e times cap x
B
29 comma 980 times open paren 1 over 5000 close paren plus 80 times open paren 1 over 1000 close paren is equal to cap e times cap x
C
29 comma 980 times open paren 1 over 5000 close paren plus 80 times open paren 1 over 1000 close paren plus negative 20 times open paren 2497 over 2500 close paren is equal to cap e times cap x
D
30 comma 000 times open paren 1 over 5000 close paren plus 100 times open paren 1 over 1000 close paren is equal to cap e times cap x

Explanation

Expected value uses each possible net gain multiplied by its probability. If a ticket wins the car, the net gain is $30,000 − $20 = $29,980, with probability 1/5,000. A gift-card winner nets $100 − $20 = $80, and the five gift cards give probability 5/5,000 = 1/1,000. The other 4,994 tickets lose, so their net gain is −$20 with probability 4,994/5,000 = 2,497/2,500; this is the equation in choice C.

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