Consider the radical equation square root of c plus 22 end root is equal to c plus 2 Which statement is true about the solutions c is equal to 3 and c is equal to negative 6 ?

Check each value in the original equation, √(c + 22) = c + 2. For c = 3, both sides equal 5, so it is a true solution. For c = −6, the left side is √16 = 4, while the right side is −4; since these are not equal, c = −6 is an extraneous solution.

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