Consider the radical equation square root of n plus 4 end root is equal to n minus 2 Which statement is true about the solutions n is equal to 5 and n is equal to 0 ?

Substitute each value into the original equation √(n + 4) = n − 2. For n = 5, both sides equal 3, so it is a solution. For n = 0, the left side is 2 but the right side is −2, so it does not satisfy the equation; it is the extraneous solution.

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