What is the simplest form of cube root of 27 A cubed b to the 7th power ?

Separate the perfect cubes inside the radical: 27 = 3³, A³ is a cube, and b⁷ = b⁶ · b = (b²)³ · b. Taking the cube root of each perfect cube gives 3Ab², leaving √[3]{b}. So the simplest form is 3Ab²√[3]{b}, choice D.

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