By examining electron domain geometry, one can determine that the ammonia molecule open paren NH sub 3 close paren has

Nitrogen in NH₃ has three N–H bonds and one lone pair, making four electron domains. Four electron domains have a tetrahedral electron-domain geometry and correspond to sp³ hybridization, which produces four sp³ orbitals. Therefore, the correct choice is “four sp³ orbitals.”

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