A 115.0-g sample of oxygen was produced by heating 400.0 g of potassium chlorate. 2 KClO sub 3 rightarrow 2 KCl plus 3 cap o sub 2 What is the percent yield of oxygen in this chemical reaction? Use percent Yield is equal to Actual yield over Theoretical yield times 100

First find the theoretical oxygen yield using the balanced equation: 2 mol KClO₃ produce 3 mol O₂. The 400.0 g of KClO₃ corresponds to about 3.263 mol, which can produce 3.263 × (3/2) × 32.00 = 156.6 g O₂. Percent yield = (115.0 g ÷ 156.6 g) × 100 = 73.40%, so the correct choice is D, 73.40%.

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