Question 4 • Algebra II
Time starts at t = 0, and the object remains in the model until it reaches the ground, where h(t) = 0. Solving −4.92t² + 17.69t + 575 = 0 gives a positive time of about 12.76 seconds, so the domain is [0, 12.76]. The parabola reaches its maximum at t = −17.69/(2 × −4.92) ≈ 1.80 seconds, where the height is about 590.90 meters; therefore the range is [0, 590.90]. Choice B gives these intervals.
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