The tables represent two linear functions in a system. x y negative 6 negative 22 negative 3 negative 10 0 2 3 14 x y negative 6 negative 30 negative 3 negative 21 0 negative 12 3 negative 3 What is the solution to this system?

In the first table, y increases by 12 when x increases by 3, so its slope is 4; since y = 2 when x = 0, the function is y = 4x + 2. In the second table, y increases by 9 when x increases by 3, so its slope is 3; since y = -12 when x = 0, the function is y = 3x - 12. Set the functions equal: 4x + 2 = 3x - 12, giving x = -14 and y = -54. The solution is choice B, negative 14 comma negative 54.

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