What are the coordinates of the vertex of the function f of x is equal to x squared plus 10 x minus 3 ?

For f(x) = x² + 10x − 3, the vertex’s x-coordinate is −b/(2a) = −10/(2 × 1) = −5. Substituting −5 into the function gives f(−5) = 25 − 50 − 3 = −28. The vertex is (−5, −28), which is choice D.

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