Question 9 • CMS 2026-2027 NC Math 1 CREDIT RECOVERY
What are the solutions to the quadratic equation open paren 5 y plus 6 close paren squared is equal to 24 ?
Answer
A
y is equal to the fraction with numerator 4 square root of 6 and denominator 5 and y is equal to the fraction with numerator 8 square root of 6 and denominator 5
B
y is equal to the fraction with numerator negative 4 square root of 6 and denominator 5 and y is equal to the fraction with numerator negative 8 square root of 6 and denominator 5
C
y is equal to the fraction with numerator negative 6 plus 2 square root of 6 and denominator 5 and y is equal to the fraction with numerator 6 minus 2 square root of 6 and denominator 5
D
y is equal to the fraction with numerator negative 6 plus 2 square root of 6 and denominator 5 and y is equal to the fraction with numerator negative 6 minus 2 square root of 6 and denominator 5
Explanation
Take the square root of both sides: 5y + 6 = ±√24 = ±2√6. Subtract 6 and divide by 5 to get y = (−6 ± 2√6)/5. These are the two values shown in choice D.
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