What is the equation, in slope-intercept form, of the line that is perpendicular to the line y minus 4 is equal to negative 2 thirds times open paren x minus 6 close paren and passes through the point open paren negative 2 comma negative 2 close paren ?

The given line has slope −2/3, so a perpendicular line has slope 3/2, the negative reciprocal. Using the point (−2, −2) in y = (3/2)x + b gives −2 = (3/2)(−2) + b, so b = 1. The equation is y = (3/2)x + 1, which is choice D.

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