Two students from a group of eight boys and 12 girls are sent to represent the school in a parade. If the students are chosen at random, what is the probability that the students chosen are not both girls?

There are 20 students altogether, so the number of possible pairs is C(20, 2) = 190. The number of pairs consisting of two girls is C(12, 2) = 66, so 190 − 66 = 124 pairs are not both girls. Thus the probability is 124/190 = 62/95, which is choice D, “62 over 95.”

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