Question 4 • Grade 7 Mathematics
Because each winning ticket is thrown away, the draws are without replacement. Jason’s chance of winning the first prize is 10/30; if he wins, his chance of winning the second is 9/29, and then 8/28 for the third. Multiply: (10/30)(9/29)(8/28) = 6/203, so the probability is 6 over 203.
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