Question 6 • Pre-Algebra B
For the first position, Geraldine can choose any of the 10 digits. Since each digit can be used only once, there are then 9 choices for the second position, 8 for the third, and 7 for the fourth. Thus, 10 × 9 × 8 × 7 = 5,040 different passwords, which is choice C.
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