15
QuizMultiple Choice

Probability — Test

Question 15 • Algebra 2 with Probability

For students majoring in Hospitality Management, it was determined that 5 percent have visited 1 – 10 states, 16 percent have visited 11 – 20 states, 45 percent have visited 21 – 30 states, 19 percent have visited 31 – 40 states, and 15 percent have visited 41 – 50 states. Suppose a Hospitality Management student is randomly selected. What is the probability that the student has visited 21 or more states?

Answer
A
0 point 7 9
B
0 point 4 5
C
0 point 2 1
D
0 point 1 5

Explanation

A student who has visited 21 or more states falls in one of the 21–30, 31–40, or 41–50 groups. Add their percentages: 45% + 19% + 15% = 79%, which is 0.79 as a probability. The correct choice is 0.79.

AI-written and checked against the verified answer.

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