A restaurant offers three vegetable side dishes, two fruit side dishes, and five grain-based side dishes. Each entree comes with two side dishes.What is the approximate probability of randomly choosing one vegetable and one grain-based side dish?

There are 10 side dishes total, so the number of ways to choose two is 10 × 9 ÷ 2 = 45. A favorable pair has one vegetable and one grain-based side dish, giving 3 × 5 = 15 possible pairs. The probability is 15 ÷ 45 = 0.33333, so the answer is D, 0.33333.

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