A discount book store sells hardcover books for $8 each and paperbacks for $4 each.The number of hardcover books, h, sold one day was 2 more than four times the number of paperback books, p, sold that same day. The total amount of sales for that day was $160. Jean-Paul wrote the following system of linear equations to find the number of each type of book sold. 8 h plus 4 p is equal to 160 p is equal to 4 h plus 2 What is Jean-Paul’s error?
Answer
A
Jean-Paul should have written the second equation as p plus 2 is equal to 4 h .
B
Jean-Paul should have written the first equation as 4 h plus 8 p is equal to 160 .
C
Jean-Paul should have written the first equation as h plus p is equal to 160 .
D
Jean-Paul should have written the second equation as h is equal to 4 p plus 2 .
Explanation
The sales equation 8h + 4p = 160 is correct because each hardcover costs $8 and each paperback costs $4. The statement says the number of hardcovers, h, was 2 more than four times the number of paperbacks, p. That translates to h = 4p + 2, so Jean-Paul wrote the second equation with the variables reversed. Choice D gives the correct equation.
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