Given log_3⁡2≈0.631 and the log base 3 of 7 almost equal to 1 point 7 7 1 , what is the log base 3 of 14 ?

Use the product rule for logarithms: log₃(14) = log₃(2 × 7) = log₃(2) + log₃(7). Substituting the given approximations gives 0.631 + 1.771 = 2.402, so the answer is choice C, 2.402.

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