What is the vertex of the graph of the function f of x is equal to x squared plus 8 x minus 2 ?

For a quadratic f(x) = ax² + bx + c, the vertex’s x-coordinate is -b/(2a). Here a = 1 and b = 8, so x = -8/2 = -4. Substituting gives f(-4) = (-4)² + 8(-4) - 2 = 16 - 32 - 2 = -18, so the vertex is negative 4 comma negative 18.

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