Question 1 • Algebra I
The factors are zero at x = 1 and x = −4, so the graph crosses the x-axis at (1, 0) and (−4, 0). The coefficient of x² is positive, so the parabola opens upward. Its vertex lies halfway between the roots, at x = (1 + (−4))/2 = −1.5; substituting gives f(−1.5) = (−2.5)(2.5) = −6.25. This matches choice B, which opens up and has a vertex near (−1.75, −6.2).
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