The axis of symmetry for the function f(x) = −x2 − 10x + 16 is x = −5. What are the coordinates of the vertex of the graph?

The vertex lies on the axis of symmetry, so its x-coordinate is −5. Substitute −5 into f(x) = −x² − 10x + 16: f(−5) = −25 + 50 + 16 = 41. Therefore, the vertex is (−5, 41), choice A.

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