Question 8 • Algebra 2
Since the zeros are 6 and 42, the boundary can be written as y = a(x − 6)(x − 42). Substituting the point (15, 81) gives 81 = a(9)(−27), so a = −1/3. Expanding gives y = −1/3x² + 16x − 84. Values above the boundary have greater y-values, so the inequality is y > −1/3x² + 16x − 84, choice C.
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