Solve the radical equation. square root of 8 x plus 9 end root is equal to x plus 2 Which is an extraneous solution to the radical equation?

Squaring both sides gives 8x + 9 = (x + 2)², so x² − 4x − 5 = 0, which factors as (x − 5)(x + 1) = 0. The possible solutions are x = 5 and x = −1. Checking them in the original equation, both work: √49 = 7 for x = 5, and √1 = 1 for x = −1. Therefore, there are no extraneous solutions.

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