How many extraneous solutions does the equation have? the fraction with numerator 9 and denominator n squared plus 1 is equal to the fraction with numerator n plus 3 and denominator 4

The denominators are n² + 1 and 4. For real n, n² + 1 is always positive, and 4 is never zero, so multiplying both sides by the denominators cannot introduce any extraneous solutions. Therefore, the equation has 0 extraneous solutions, which is choice B.

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