What is the solution to the equation the fraction with numerator negative 3 d and denominator d squared minus 2 d minus 8 plus the fraction with numerator 3 and denominator d minus 4 is equal to the fraction with numerator negative 2 and denominator d plus 2 ?

Factor the quadratic denominator: d² − 2d − 8 = (d − 4)(d + 2), so d cannot be 4 or −2. Combining the left-hand fractions gives 6/[(d − 4)(d + 2)] = −2/(d + 2). Since d ≠ −2, cancel d + 2 and solve 6/(d − 4) = −2, which gives d = 1. The correct choice is D, d is equal to 1.

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