Rational Equations Answers
Question text not available
Name the true solution(s) to the equation.x = 0x = 1x = 8x = 0, x = 1, and x = 8 x = 1 and x = 8There are no solutions.
Name the extraneous solution(s) to the equation.x = 0x = 1x = 8x = 0, x = 1, and x = 8x = 1 and x = 8There are no extraneous
Solve: The solution is a =
1/6
Solve and check The solution is c =
14
What are the solutions to the equation?
After multiplying each side of the equation by the LCD and simplifying, the resulting equation is 3x² – 20x + 12 = 03x² – 20x – 12 = 03x² + 20x + 12 = 03x² + 20x – 12 = 0.
1 x + 3
x = 1 is a solution.x = 0 is a solution.x = –1 is a solution.x = –6 is a solution.
Question text not available
Solve: The solution is a =
1/6
After multiplying each side of the equation by the LCD and simplifying, the resulting equation is 3x² – 20x + 12 = 03x² – 20x – 12 = 0✔ 3x² + 20x + 12 = 03x² + 20x – 12 = 0.
What are the solutions to the equation?
⇒ -8
x = 1 is a solution.x = 0 is a solution.x = –1 is a solution.x = –6 is a solution.
Question text not available
Name the true solution(s) to the equation.X x = 0x = 1x = 8x = 0, x = 1, and x = 8✔ x = 1 and x = 8There are no solutions.
Question text not available
No, the student is incorrect. When solving the equation, the algebraic solution found is a = –2. However, this value must be checked against the restrictions of the original equation. Substituting –2 into the denominators (a + 2) and (a^2 – 4) results in division by zero, which is undefined. Therefore, a = –2 is an extraneous solution, and the original rational equation actually has no solution.
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