AnswersINMT3 Integrated Math 3 Sem 1 26-27Solving Polynomial Equations using Technology

Rational Equations Answers

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1
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Which solution to the equation is extraneous?

Question illustration
A
x = 1 and x = –4
B
neither x = 1 or x = –4
C
x = 1
D
x = –4
2
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What are the solutions to the equation ?

Question illustration
A
w = –6 and w = –2
B
w = 0, w = 2, and w = 6
C
w = 0 and w =
Option C
D
w = 2 and w = 6
3

How many extraneous solutions does the equation below have?

Question illustration
A
0
B
1
C
2
D
3
4

What causes a solution to a rational equation to be an extraneous solution?

A
When there is more than one solution, one of the solutions is extraneous.
B
If a solution results in zero when substituted into the denominator of the equation, the solution is extraneous.
C
If a solution results in a negative number when substituted into the denominator of the equation, the solution is extraneous.
D
When a solution is a fraction, the solution is extraneous.
5

Consider the graph showing two functions. Which answer can be used to find the solution to the system of equations?

Question illustration
A
Option
Option A
B
Option
Option B
C
Option
Option C
D
Option
Option D
6

Janet wants to solve the equation . What should she multiply both sides of the equation by?

Question illustration
A
y
B
y2 – 1
C
y + 1
D
y2 + y + 2
7

Which of the following represents the solution of ?

Question illustration
A
x = one-fifth
Option A
B
x = five-ninths
Option B
C
all real numbers
D
no solution
8

Kent multiplies both sides of the equation below by an expression.Then he moves all the terms to one side of the equal sign in the resulting equation. Which equation must he solve now?

Question illustration
A
k squared minus 8 k minus 12 = 0
Option A
B
k squared + 8 k + 12 = 0
Option B
C
k squared minus 8 + 12 = 0
Option C
D
k squared minus 8 k + 12 = 0
Option D
9

What is the solution to the equation ?

Question illustration
A
h = eleven-thirds
Option A
B
h = 5
Option B
C
h = 7
Option C
D
h = twenty-one-halves
Option D
10

What are the solutions to the equation

Question illustration
A
x = –7 and x = 1
B
x = –6 and x = –1
C
x = –1 and x = 7
D
x = 1 and x = 6

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