How many extraneous solutions does the equation have? the fraction with numerator 2 m and denominator 2 m plus 3 minus the fraction with numerator 2 m and denominator 2 m minus 3 is equal to 1

The denominators cannot be zero, so m cannot equal 3/2 or −3/2. Combining the fractions gives −12m/(4m² − 9) = 1, which leads to 4m² + 12m − 9 = 0. Its solutions are (−3 + 3√2)/2 and (−3 − 3√2)/2; neither is excluded by the denominator restrictions. Therefore, there are 0 extraneous solutions, choice B.

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