Question 22 • Precalculus
The denominator x² − 1 is zero at x = −1 and x = 1, so the graph has vertical asymptotes there. Since the denominator’s degree is greater than the numerator’s, the horizontal asymptote is y = 0. Between −1 and 1, the graph goes from positive infinity to negative infinity and crosses the origin, where f(0) = 0. These features match choice D.
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