Which statement is true about the discontinuities of the function f of x ? f of x is equal to the fraction with numerator x plus 1 and denominator 6 x squared minus 7 x minus 3

Factor the denominator: 6x² − 7x − 3 = (3x + 1)(2x − 3). It is zero at x = −1/3 and x = 3/2. Neither factor cancels with the numerator x + 1, so these discontinuities are vertical asymptotes, not holes. The correct statement is that there are asymptotes at x = 3/2 and x = −1/3.

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