What is the solution of the fraction with numerator negative 8 and denominator 2 y minus 8 is equal to the fraction with numerator 5 and denominator y plus 4 minus the fraction with numerator 7 y plus 8 and denominator y squared minus 16 ?

The denominators require y ≠ 4 and y ≠ −4. Since y² − 16 = (y − 4)(y + 4) and 2y − 8 = 2(y − 4), rewrite both sides over the common denominator (y − 4)(y + 4): −4(y + 4) = 5(y − 4) − (7y + 8) = −2y − 28. Solving −4y − 16 = −2y − 28 gives y = 6, so the solution is choice A, y is equal to 6.

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