What is the solution of the fraction with numerator 3 x plus 8 and denominator x minus 4 is greater than or equal to 0 ?

The numerator is zero at x = -8/3, and the denominator is zero at x = 4, where the fraction is undefined. Checking the intervals determined by these values shows the fraction is nonnegative when x ≤ -8/3 or x > 4. The value -8/3 is included because it makes the fraction zero; 4 is excluded because the denominator is zero. So the solution is “x is less than or equal to negative 8 thirds or x is greater than 4.”

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