6
QuizMultiple Choice

Reaction Rates and Equilibrium — Test

Question 6 • Chemistry

Consider the equation below. CaCO sub 3 times s long left right arrow CaO times s plus CO sub 2 times g What is the equilibrium constant expression for the given reaction?

Answer
A
cap k sub e q is equal to the fraction with numerator open bracket CO sub 2 close bracket times CaO and denominator open paren CaCO sub 3 close paren
B
cap k sub e q is equal to the fraction with numerator 1 and denominator open paren CO sub 2 close paren
C
cap k sub e q is equal to open bracket CO sub 2 close bracket
D
cap k sub e q is equal to the fraction with numerator CaO and denominator open paren CaCO sub 3 close paren

Explanation

For an equilibrium expression, pure solids are omitted because their activities are constant. CaCO₃(s) and CaO(s) are both solids, so only gaseous CO₂ appears: Kₑq = [CO₂], which is choice C.

AI-written and checked against the verified answer.

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