Point P is located at (–3, –2). P is reflected across the x-axis to create P'. What quadrant is P' in?

Reflecting a point across the x-axis keeps its x-coordinate the same and changes the sign of its y-coordinate. So P = (–3, –2) becomes P' = (–3, 2). Its x-coordinate is negative and its y-coordinate is positive, placing P' in Quadrant II, choice B.

AI-written and checked against the verified answer.