3
QuizMultiple Choice

Relative Frequencies and Association — Quiz

Question 3 • Mathematics I

The frequency table represents the job status of a number of high school students. Job Status Looking for Job Not Looking for Job Total Currently Employed 12 28 40 Not Currently Employed 38 72 110 Total 50 100 150 Which shows the conditional relative frequency table by column?

Answer
A
Job Status Table with 4 columns and 4 rows.Row 1: Column 1, empty; Column 2, 'Looking for Job'; Column 3, 'Not Looking for Job'; Column 4, 'Total' Row 2: Column 1, 'Currently Employed'; Column 2, '0 point 3'; Column 3, '0 point 7'; Column 4, 'almost equal to 0 point 2 7' Row 3: Column 1, 'Not Currently Employed'; Column 2, 'almost equal to 0 point 3 3'; Column 3, 'almost equal to 0 point 6 5'; Column 4, 'almost equal to 0 point 7 3' Row 4: Column 1, 'Total'; Column 2, '1 point 0'; Column 3, '1 point 0'; Column 4, '1 point 0'
B
Job Status Table with 4 columns and 4 rows.Row 1: Column 1, empty; Column 2, 'Looking for Job'; Column 3, 'Not Looking for Job'; Column 4, 'Total' Row 2: Column 1, 'Currently Employed'; Column 2, '0 point 1 2'; Column 3, '0 point 2 8'; Column 4, '0 point 4' Row 3: Column 1, 'Not Currently Employed'; Column 2, '0 point 3 8'; Column 3, '0 point 7 2'; Column 4, '1 point 1' Row 4: Column 1, 'Total'; Column 2, '0 point 5 0'; Column 3, '1 point 0 0'; Column 4, '1 point 5'
C
Job Status Table with 4 columns and 4 rows.Row 1: Column 1, empty; Column 2, 'Looking for Job'; Column 3, 'Not Looking for Job'; Column 4, 'Total' Row 2: Column 1, 'Currently Employed'; Column 2, '0 point 2 4'; Column 3, '0 point 2 8'; Column 4, 'almost equal to 0 point 2 7' Row 3: Column 1, 'Not Currently Employed'; Column 2, '0 point 7 6'; Column 3, '0 point 7 2'; Column 4, 'almost equal to 0 point 7 3' Row 4: Column 1, 'Total'; Column 2, '1 point 0'; Column 3, '1 point 0'; Column 4, '1 point 0'
D
Job Status Table with 4 columns and 4 rows.Row 1: Column 1, empty; Column 2, 'Looking for Job'; Column 3, 'Not Looking for Job'; Column 4, 'Total' Row 2: Column 1, 'Currently Employed'; Column 2, '0 point 0 8'; Column 3, 'almost equal to 0 point 1 9'; Column 4, 'almost equal to 0 point 2 7' Row 3: Column 1, 'Not Currently Employed'; Column 2, 'almost equal to 0 point 2 5'; Column 3, '0 point 4 8'; Column 4, 'almost equal to 0 point 7 3' Row 4: Column 1, 'Total'; Column 2, 'almost equal to 0 point 3 3'; Column 3, 'almost equal to 0 point 6 7'; Column 4, '1 point 0'

Explanation

For a conditional relative frequency table by column, divide each count by its column total. In the Looking for Job column, 12 ÷ 50 = 0.24 and 38 ÷ 50 = 0.76; in the Not Looking for Job column, 28 ÷ 100 = 0.28 and 72 ÷ 100 = 0.72. The Total column is 40 ÷ 150 ≈ 0.27 and 110 ÷ 150 ≈ 0.73, so choice C has the correct values.

AI-written and checked against the verified answer.

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