Right Triangle Relationships and Trigonometry — Test
Question 2 • Geometry
Given triangle JKL , sine of open paren 38 degrees close paren equals
Answer
A
cosine of open paren 52 degrees close paren .
B
tangent of open paren 52 degrees close paren .
C
tangent of open paren 38 degrees close paren .
D
cosine of open paren 38 degrees close paren .
Explanation
Sine and cosine of complementary angles are equal: sin(θ) = cos(90° − θ). Since 90° − 38° = 52°, sin(38°) = cos(52°). Therefore, the correct choice is cosine of 52 degrees.
AI-written and checked against the verified answer.