Find the first three iterates of the function f(z) = 2z + (3 - 2i) with an initial value of z0 = 4.

Apply the function repeatedly, starting with z₀ = 4. First, z₁ = 2(4) + (3 − 2i) = 11 − 2i. Then z₂ = 2(11 − 2i) + (3 − 2i) = 25 − 6i, and z₃ = 2(25 − 6i) + (3 − 2i) = 53 − 14i. The correct choice is D: 11 − 2i, 25 − 6i, 53 − 14i.

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