As a mass on a spring moves farther from the equilibrium position, how do the velocity, acceleration, and force change?

As the mass moves farther from equilibrium, it moves toward a turning point, where its speed is lower. Hooke’s law says the restoring force’s magnitude is F = kx, so it increases with distance x from equilibrium; since acceleration is F/m, its magnitude increases too. Thus the velocity (speed) decreases while the acceleration and net force increase in magnitude, matching choice A.

AI-written and checked against the verified answer.