What is the energy of a photon with a frequency of 3.6 × 1015 Hz? Planck’s constant is 6.63 × 10–34 J•s.

Use the photon energy formula E = hf, where h is Planck’s constant and f is frequency. Multiplying (6.63 × 10⁻³⁴ J·s)(3.6 × 10¹⁵ Hz) gives 23.868 × 10⁻¹⁹ J, or about 2.4 × 10⁻¹⁸ J. Therefore, the correct choice is D, 2.4 × 10⁻¹⁸ J.

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