AnswersFL-1200330-Algebra 2 CRSolving Equations using Properties of LogarithmsQuestion 7
7
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Solving Equations using Properties of Logarithms

Question 7 • FL-1200330-Algebra 2 CR

⇒ 2

Answer
x2 − 2x − 15 = 0:

2

Potential solutions are −3 and 5:

5

x2 − 15 = 2x:

1

x − 5 = 0 or x + 3 = 0:

4

(x − 5)(x + 3) = 0:

3

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