Solving Equations using Properties of Logarithms

Question 1

Solve the equation log4(x + 20) = 3x =

Revolt · Accepted Answer

44

Question 2

Solve the equation log6(13 – x) = 1.x =

Revolt · Accepted Answer

7

Question 3

⇒ 2 x2 − 2x − 15 = 0 Potential solutions are −3 and 5 x2 − 15 = 2x x − 5 = 0 or x + 3 = 0 (x − 5)(x + 3) = 0

Revolt · Accepted Answer

⇒ 2: Given equation; Part 2: 5; Part 3: 1; Part 4: 4; Part 5: 3

Question 4

Find the potential solution to the equationlog4(2 – x) = log4(–5x – 18).x =

Revolt · Accepted Answer

-5

Question 5

Which is the only solution to the equationlog3(x2 + 6x) = log3(2x + 12)?

Revolt · Accepted Answer

x = 2

Question 6

Which shows the first step in the solution to the equation log2x + log2(x – 6) = 4?

Revolt · Accepted Answer

log2[x(x – 6)] = 4

Question 7

What are the solutions tolog3x + log3(x2 + 2) = 1 + 2log3x?

Revolt · Accepted Answer

x = 1; x = 2

Question 8

x = ⇒ -3 or x =

Revolt · Accepted Answer

Part 2: 3

Question 9

Which statement is true about the potential solution x = –5?

Revolt · Accepted Answer

This number is a true solution of the original equation.

Question 10

Which equation can you solve to find the potential solutions to the equation log2x + log2(x – 6) = 4?

Revolt · Accepted Answer

x2 – 6x – 16 = 0

Solving Equations using Properties of Logarithms Answers