AnswersDHS Algebra 2 VBase e

Solving Exponential and Logarithmic Equations Answers

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1
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Answers:
are equal:bases
must also be equal.:exponents
2
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, the basesexponentsequationsvariables must also be equal.

A
bases
B
exponents
C
equations
D
variables
3

Because the basesexponentsequationsvariables are equal

A
bases
B
exponents
C
equations
D
variables
4

The solution to the equation is x = .

Answer:

5

5

What equation is equivalent to 9x - 3 = 729?

A
9x - 3 = 981
B
9x - 3 = 93
C
3x - 3 = 36
D
32x - 3 = 36
6

To solve 5(2x + 4) = 15, first divide each side by .

Answer:

5

7

Which of the following is the solution of 5e2x - 4 = 11?

A
x = ln 3
B
x = ln 27
C
Option
D
Option
8

Select all of the potential solution(s) of the equation 2log5x = log54.

A
x = -2
B
x = 4
C
x = 16
D
x = -10
E
x = 2
9

Which equation is equivalent to log5x3 - logx2 = 2?

A
Option
B
Option
C
Option
10

Solve: log5x3 - logx2 = 2 x =

Answer:

20

11

What is the solution to ln (x2 - 16) = 0?

A
Option
B
Option
C
Option
12

Solve: ln 2x + ln 2 = 0x =

Answer:

1/4

13

Solve: e2x + 5 = 4

A
Option
B
Option
C
Option
14

An initial investment of $100 is now valued at $150. The annual interest rate is 5%, compounded continuously. The equation 100e0.05t = 150 represents the situation, where t is the number of years the money has been invested. About how long has the money been invested? Use your calculator and round to the nearest whole number. years

Answer:

8

15

Solve: 9x - 3 = 729x =

Answer:

6

16

Solve 5(2x + 4) = 15. Round to the nearest thousandth.

Question illustration
Answer:

-0.500

17

What is the solution to 2log5x = log54? x =

Answer:

2

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