AnswersCR CCSS Math 2 S2 M2960OXSolving for Side Lengths of Right Triangles

Solving for Side Lengths of Right Triangles Answers

13 verified answers1 views
1
Free Preview

Which equation could be used to solve for the length of XY?

A
XY = (22)sin(41°)
Option A
B
XY = (22)cos(41°)
Option B
C
XY =
Option C
D
XY =
Option D
2
Free Preview

Question text not available

Answer not available
114253

Use the diagram to complete the statements.

Answers:
The measure of angle L is °.:70
The trigonometric ratio that uses ∠M and LN to solve for NM is .:tangent
The length of NM, to the nearest tenth, is approximately .:57.7
114254

sinecosine✔ tangent

A
sine
B
cosine
C
✔ tangent
114255

7.622.3✔ 57.7

A
7.6
B
22.3
C
✔ 57.7
114257

Question text not available

Answer not available
114260

Which error did Kevin make?

A
He has the side lengths in the wrong place in the cosine ratio.
B
He multiplied both sides by the length of XZ instead of dividing by XZ.
C
He should have used the sine ratio.
D
He should have used the tangent ratio.
114261

Which equations could be used to solve for the unknown lengths of △ABC? Check all that apply.

A
sin(45°) =
Option A
B
sin(45°) =
Option B
C
9 tan(45°) = AC
D
(AC)sin(45°) = BC
E
cos(45°) =
Option E
114263

Use the diagram to complete the statements.

Answers:
The measure of angle L is °.:70
The trigonometric ratio that uses ∠M and LN to solve for NM is .:tangent
The length of NM, to the nearest tenth, is approximately .:57.7

Did you find these answers helpful?