AnswersCR CCSS Math 2 S2 M2960OXTriangle Similarity: AA

Solving for Side Lengths of Right Triangles Answers

11 verified answers
1
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Which equation could be used to solve for the length of XY?

A
XY = (22)sin(41°)
Option A
B
XY = (22)cos(41°)
Option B
C
XY =
Option C
D
XY =
Option D
2
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Which error did Kevin make?

A
He has the side lengths in the wrong place in the cosine ratio.
B
He multiplied both sides by the length of XZ instead of dividing by XZ.
C
He should have used the sine ratio.
D
He should have used the tangent ratio.
3

A 25-foot long ladder is propped against a wall at an angle of 18° with the wall. Which diagram correctly represents this scenario?

A
[Image: A ladder is propped against a 25 foot tall wall. T...]
Option A
B
[Image: A 25 foot ladder is propped against a wall forming...]
Option B
C
[Image: A ladder is propped against a wall forming an 18 d...]
Option C
D
[Image: A 25 foot ladder is propped against a wall. The an...]
Option D
5

Use the diagram to complete the statements.

Answers:
The measure of angle L is °.:70
The trigonometric ratio that uses ∠M and LN to solve for NM is .:tangent
The length of NM, to the nearest tenth, is approximately .:57.7
6

sinecosine✔ tangent

A
sine
B
cosine
C
✔ tangent
7

7.622.3✔ 57.7

A
7.6
B
22.3
C
✔ 57.7
8

X 20✔ 7090

A
X 20
B
✔ 70
C
90
9

Which equations could be used to solve for the unknown lengths of △ABC? Check all that apply.

A
sin(45°) =
Option A
B
sin(45°) =
Option B
C
9 tan(45°) = AC
D
(AC)sin(45°) = BC
E
cos(45°) =
Option E

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